Question

factorise 4x^2-4x-3​

Answer 1

here is ur answer:

$4 {x}^{2} - 4x - 3 = 0 \\ \\ 4 {x}^{2} - 6x + 2x - 3 = 0 \\ \\ 2x(2x - 3) + 1(2x - 3) = 0 \\ \\ (2x + 1)(2x - 3) = 0 \\ \\ \\ 2x + 1 = 0 \\ \\ x = - \frac{1}{2} \\ \\ 2x - 3 = 0 \\ \\ x = \frac{3}{2}$

hope it helps you!

Answer 2

Answer:

Step-by-step explanation:

= 4x^2-4x-3

= 4x^2+2x-6x-3

= 2x(2x+1)-3(2x+1)

= (2x-3) (2x+1)

2x-3=0. Or. 2x+1=0

2x=3. 2x= -1

X=3/2. X= -1/2

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