Question

factorise
4x^2-81y^2​

Answer 1

$= 4 {x}^{2} - 81 {y}^{2} \\ = (2x + 9y)(2x - 9y)$

hope it helps you.

Answer 2

Step-by-step explanation:

4

x

2

−

81

y

2

Rewrite

4

x

2

as

(

2

x

)

2

.

(

2

x

)

2

−

81

y

2

Rewrite

81

y

2

as

(

9

y

)

2

.

(

2

x

)

2

−

(

9

y

)

2

Since both terms are perfect squares, factor using the difference of squares formula,

a

2

−

b

2

=

(

a

+

b

)

(

a

−

b

)

where

a

=

2

x

and

b

=

9

y

.

(

2

x

+

9

y

)

(

2

x

−

(

9

y

)

)

Multiply

9

by

−

1

.

(

2

x

+

9

y

)

(

2

x

−

9

y

)

([)]|√>≥

789÷<≤

456/×∩∪

123-^π∞

0.,+%=

Cookies & Privacy

This w