factorise 4x^2-8x+4
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Answered by
18
4x² -8x+4
4x²-4x-4x+4
4x(x-1)-1(4x-1)
(4x-1)(4x-1)
.........> x = 1/4
x=1/4
these are the two factors of the polynomial
Thanks
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Answered by
4
Answer:
the sum is -8x and the product is 16x^2 so the required numbers are -4x and -4x
4x^2-4x-4x+4
4(x-1)-4(x-1)
(4-4)(x-1)
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