Question

Factorise
4x^2 -8x+4

Answer 1

4x² - 8x + 4

= 4x² - 4x - 4x + 4

= 4x(x - 1) - 4(x - 1)

= (4x - 4)(x - 1)

= 4(x - 1)(x - 1).

Answer 2

$hi \: ..$

$4 {x}^{2} - 8x + 4 = 0$

Dividing both sides by 4

${x}^{2} - 2x + 1 = 0$

${x}^{2} - x - x + 1 = 0$

$x(x - 1) - 1(x - 1) = 0$

$(x - 1)(x - 1) = 0$

$x - 1 = 0$

$x = 1$

This is the required solution .

hope this helps you ! ! !