factorise: 4x^2+9y^2+16z^2+12xy-24yz-16
can this question be done like this-
=(-2x) ^2+(-3y)^2+(4z) ^2+2(-2x)(-3y)+2(-3y)(4z) +2(4z)(-2x)
=using identity
(a+b+c)^2=a^2+b^2+c^2+2ab+2bc+2ca
= [-2x+(-3y)+4z]
= (-2x-3y+4z)
Answers
Answered by
5
I am not sure but it can be like that it correct.
Anonymous:
ok
Answered by
1
yes it can be done like that
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