Factorise : 4x^2 + 9y^2 + 16z^2 + 12xy -24yz - 16xz
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As per the identity (a+b+c)^2=a^2+b^2+c^2+2ab+2bc+2ac
(2x)^2+(3y)^2+(-4z)^2+2(2x)(3y)+2(2x)(-4z)+2(2x)(-4z)
So the answer is (2x+3y-4z)^2
(2x)^2+(3y)^2+(-4z)^2+2(2x)(3y)+2(2x)(-4z)+2(2x)(-4z)
So the answer is (2x+3y-4z)^2
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