factorise:- 4x^2+9y^2+16z^2+12xy-24yz-16xz
Answers
Answered by
38
The answer is given below :
We know that :
(x + y - z)²
= x² + y² + z² + 2xy - 2yz - 2xz
Given,
4x² + 9y² + 16z² + 12xy - 24yz - 16xz
= (2x)² + (3y)² + (4z)² + (2 × 2x × 3y) - (2 × 3y × 4z) - (2 × 2x × 4z)
= (2x + 3y - 4z)²
= (2x + 3y - 4z)(2x + 3y - 4z)
Thank you for your question.
We know that :
(x + y - z)²
= x² + y² + z² + 2xy - 2yz - 2xz
Given,
4x² + 9y² + 16z² + 12xy - 24yz - 16xz
= (2x)² + (3y)² + (4z)² + (2 × 2x × 3y) - (2 × 3y × 4z) - (2 × 2x × 4z)
= (2x + 3y - 4z)²
= (2x + 3y - 4z)(2x + 3y - 4z)
Thank you for your question.
Answered by
9
Answer:
Step-by-step explanation:
Attachments:
Similar questions