Question

factorise 4x^2+9y^2+16z^2+12xy-24yz-16xz​

Answer 1

Answer:(-2x-3y+4z)^2

Step-by-step explanation:

Answer 2

Answer:

★question :-

† factorise :

4x^2+9y^2+16z^2+12xy-24yz-16xz

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● Identity

An identity is an equality which is true find all

values of a variable in the equality .

In an identity the right hand side expression is called expanded form of the left hand side expression.

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Now comparing that with the identity

⟹ (a^2+b^2+b^2) =2ab+2bc+2ac

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† Solution :-

We can we write the given expressions-

Now we get :

4x^2+9y^2+16z^2+12xy-24yz-16xz

: ⟹ 2x^2+3y^2+4z^2+ 2×2x×3y+2×3y×(-4z) +2×2x×(-4z)

: ⟹ [ 2x+3y+(-4z)]^2

: ⟹[ 2x+3y-4z] [ 2x+3y-4z]

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Required Answer :

⟹ ( 2x+3y-4z) ( 2x+3y-4z)

★ Identity used :

[(a^2+b^2+c^2) =2ab+2bc+2ac]

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I hope this is helpful ☺️