Question

factorise 4x^2+9y^2-25z^2+12xy

Answer 1

4x^2+9y^2-25z^2+12xy
=(2x)^2+(3y)^2+2×2x×3y-25z^2
=(2x+3y)^2-(5y)^2
=(2x+3y-5z)(2x+3y+5z)
Hope it will help u.

Answer 2

Answer: The factorisation form will be (2x+3y-5x)(2x+3y+5z).

Step-by-step explanation:

Since we have given that

$4x^2+9y^2-25x^2+12xy$

We need to find the factorisation:

$(4x^2+9y^2+12xy)-25z^2\\\\Using\ (a+b)^2=a^2+b^2+2ab\\\\=(2x)^2+(3y)^2+2\times 2x\times 3y-(5z)^2\\\\=(2x+3y)^2-(5z)^2\\\\Using\ a^2-b^2=(a-b)(a+b)\\\\=(2x+3y-5z)(2x+3y+5z)$

Hence, the factorisation form will be (2x+3y-5x)(2x+3y+5z).