Question

Factorise
(4x-5y)² -16z²

Answer 1

Solution:

Now, $(4x-5y)^{2}-16z^{2}$

$=(4x-5y)^{2}-(4z)^{2}$

Use the identity: $a^{2}-b^{2}=(a+b)(a-b)$

$=(4x-5y+4z)(4x-5y-4z)$

This is the required factorization.

Answer 2

Answer:

(4x-5y+4z) (4x-5y-4z)

Step-by-step explanation:

(4x-5y)² - (4z)² (Because 16's square is 4)

You should use a²-b²=(a+b) (a-b) as formula

And there you go...Your answer is

(4x-5y+4z) (4x-5y-4z)