Question

factorise 4x square + 4 x minus 3​

Answer 1

⭐Answer:

4x²+4x-3=0

→ 4x²+6x-2x-3=0

→ 2x(2x+3) -1(2x+3) =0

→ (2x-1) (2x+3) =0

→ (2x-1) =0 OR (2x+3) =0

→ x= 1/2 OR x= -3/2

Therefore,

(1/2, -3/2) are the roots of the given quadratic equation.

Answer 2

Answer:

(2x - 1)(2x + 3)

Step-by-step explanation:

ax² + bx + c = a(x - $x_{1}$)(x - $x_{2}$)

f(x) = 4x² + 4x - 3

D = 16 - 4(- 3)(4) = 64 = 8²

$x_{1}$ = ( - 4 - 8) / 8 = - 3/2

$x_{2}$ = ( - 4 + 8) / 8 = 1/2

4x² + 4x - 3 = 4(x - 1/2)(x + 3/2) = (2x - 1)(2x + 3)