factorise 4x square+y square +z square -4xy-2yz+4xz
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Answer:
4x²+y²+z²-4xy-2yz+4xz
(2x)²+(-y)²+(z)²+2(2x)(-y)+2(-y)(z)+2(2x)(z)
Therefore , by using
(a+b+c)²=a²+b²+c²+2ab+2bc+2ca
[2x+(-y)+z]²
(2x-y+z)²
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