Question

factorise 4x(x-4)^2 - 9(x-4)^3 by taking out common factors​

Answer 1

Answer:

5x- 16 ×2-9x+36

5x-32-9x+36

-4x+ 4

so, x=4÷4

=1

Answer 2

Answer:

( x-4)²{4-9(x-4)}

( x-4)²{4-9(x-4)}(x²+ 4²- 8x) (4- 9x+36)

( x-4)²{4-9(x-4)}(x²+ 4²- 8x) (4- 9x+36)( x²+ 16 - 8x) ( 40- 9x)

( x-4)²{4-9(x-4)}(x²+ 4²- 8x) (4- 9x+36)( x²+ 16 - 8x) ( 40- 9x) ( x - 4) ( x-4) ( 40 - 9x)

Step-by-step explanation:

I hope its helpful