Factorise - 4x2 + 25y2 + 20xy - 10x - 25y
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Consider, 4x2 + 25y2 + 20xy - 10x - 25y
= (4x2 + 20xy + 25y2) - 10x - 25y
= [(2x)2 + 2 × 2x × 5y + (5y)2] - 10x - 25y
= [(2x + 5y)2] - 5[2x + 5y]
= (2x + 5y) [(2x + 5y) - 5]
= (4x2 + 20xy + 25y2) - 10x - 25y
= [(2x)2 + 2 × 2x × 5y + (5y)2] - 10x - 25y
= [(2x + 5y)2] - 5[2x + 5y]
= (2x + 5y) [(2x + 5y) - 5]
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