Question

factorise :- 4x2 +4xy +y2​

Answer 1

in order to see the step-by-step solution please seeing attachment b

Answer 2

Answer:

$\large{\underline{\boxed{\sf (2x + y)(2x + y) }}}$

Step-by-step explanation:

4x² + 4xy + y²

We can bring this equation in the form of (a + b)². Here we go -

4x² + 4xy + y²

⇒ (2x)² + 2 * 2x * y + (y)²

⇒ (2x + y)²

[(a + b)² = a² + 2ab + b²]

⇒ (2x + y)(2x + y)

Hence, the answer is (2x + y)(2x + y).

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$\large{\underline{\underline{\mathfrak{\heartsuit \: Algebraic \: Identities : \: \heartsuit}}}}$

• (a - b)³ = a³ - b³ - 3ab (a - b)
• (a + b)³ = a³ + b³ + 3ab (a + b)
• (a + b)² = a² + 2ab + b²
• (a - b)² = a² - 2ab + b²
• a³ + b³ = (a + b) (a² - ab + b²)
• a³ - b³ = (a - b)(a² + ab + b²)
• (x + a)(x + b) = x² + x(a + b) + ab