factorise 4x2-4xy+y2-9z2
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Answered by
49
4x^2 - 4xy + y^2 - 9z^2
= (2x - y + 3z)(2x -y - 3z).
= (2x - y + 3z)(2x -y - 3z).
yash384:
thank you so much but can you expand this. I want to see that how you done this
(2x - y + 3z)(2x - y - 3z)
= 4x^2 - 2xy - 6xz - 2xy + y^2 + 3yz + 6xz - 3zy - 9z^2
= 4x^2 + y^2 - 4xy + 3yz - 3zy - 9z^2
= 4x^2 + y^2 - 4xy - 9z^2.
= 4x^2 - 2xy - 6xz - 2xy + y^2 + 3yz + 6xz - 3zy - 9z^2
= 4x^2 + y^2 - 4xy + 3yz - 3zy - 9z^2
= 4x^2 + y^2 - 4xy - 9z^2.
Did u get it?
Answered by
7
Answer:
(2x-y+3z)(2x-y-3z)
#hope this helps you.
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