Question

Factorise : 4x2 +9y2 + 16z2 + 12xy - 24yz - 16xz.

Answer 1

Step-by-step explanation:

${4x}^{2} + {9y}^{2} + {16z}^{2} + 12xy - 24yz - 16xz$

=2x+3y+4z+2×2x×3y-2×3y×4z-2×2x×4z

=

${(2x + 3y - 4z)}^{2}$

$[by \: using \: identity \: a {}^{2} + {b}^{2} + {c}^{2} + 2ab + 2bc + 2ac = {(a + b + c)}^{2}]$

= (2x+3y-4z)(2x+3y-4z)

Answer 2

$\huge\boxed{\underline{\mathcal{\red{A}\green{N}\pink{S}\orange{W}\blue{E}\pink{R}}}}$

4x²+9y²+16z²+12xy-24yz-16xz.

(2x) ² + (3y) ² +( 4z) ² + 2(3y.2x)+(-3y. 4z) +(4z.2x)

$\huge{\fbox{\fbox{\orange{\mathfrak{Concept \:Used}}}}}$

(a+b+c)²=a²+b²+c²+2(ab+bc+ba)

(2x+3y-4z)(2x+3y-4z)