Math, asked by instagram4divyesh, 10 months ago

factorise 4x²+9y²+16z²+12xy-24yz-16xz

also, which identities will be used here?​

Answers

Answered by basavaraj5392
3

Answer:

= 4x²+9y²+16z²+12xy-24yz-16xz

= (2x)²+ (3y)²+ (-4z)²+2(2x)(3y)+2(3y)(-4z)+2(2x)(-4z)

= [(2x)+(3y)+(-4z)]²

= [2x+3y-4z]²

[a+b+c]² = a²+b²+c²+2ab+2bc+2ac

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