Question

Factorise-: 4x2 +9y2 + 16z2 + 12xy - 24yz - 16zx
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Answer 1

Answer:

Step-by-step explanation:

(2x)²+(3y)²+(−4z)²+(2×2x×3y)+(2×3y×−4z)+(2×−4z×2x)

 

=(2x+3y–4z)²

Identity used:

[a²+b²+c²+2ab+2bc+2ca = (a²+b²+c²)]

 

=(2x+3y–4z) (2x+3y–4z)

Answer 2

Answer:

$4 {x}^{2} + 9 {y}^{2} + 16 {z}^{2} + 12xy - 24yz - 16xz \\ = (2x) {}^{2} + (3y {)}^{2} + ( - 4z) {}^{2} + 2 \times (2x \times 3y) + 2{3y + ( - 4z)} + 2 \times {( - 4z) \times 3y} \\ (a + b + c) {}^{2} = a {}^{2} + {b}^{2} + {c}^{2} + 2ab + 2bc + 2ac \\ = (2x + 3y - 4z) {}^{2} \\ = (2x + 3y - 4z)(2x + 3y - 4z)$

Answer:

. (2x+3y-4z)(2x + 3y - 4z)

Hope this will help you!!!