Question

Factorise : 4x2+9y2+4z2 -12xy+12yz-8zx

Answer 1

Answer:

$(-2x+3y+2z)^2$

Step-by-step explanation:

$4x^2+9y^2+4z^2-12xy+12yz-8zx\\\\=(-2x)^2+(3y)^2+(2z)^2+2(-2x)(3y)+2(3y)(2z)+2(-2x)(2z)\\\\=(-2x+3y+2z)^2$

[∵ (a + b + c)² = a² + b² + c² + 2ab + 2bc + 2ca ]

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Answer 2

Answer:

(−2x+3y+2z)

2

Step-by-step explanation:

\begin{gathered}4x^2+9y^2+4z^2-12xy+12yz-8zx\\\\=(-2x)^2+(3y)^2+(2z)^2+2(-2x)(3y)+2(3y)(2z)+2(-2x)(2z)\\\\=(-2x+3y+2z)^2\end{gathered}

4x

2

+9y

2

+4z

2

−12xy+12yz−8zx

=(−2x)

2

+(3y)

2

+(2z)

2

+2(−2x)(3y)+2(3y)(2z)+2(−2x)(2z)

=(−2x+3y+2z)

2

[∵ (a + b + c)² = a² + b² + c² + 2ab + 2bc + 2ca ]

Hope it helps!!! Please mark Brainliest!!!