Question

Factorise : 4x2 +9y2 +z2 + 12xy - 6yz - 4zx

please ans this questions ​

Answer 1

here is the answer

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Answer 2

$4 {x}^{2} + 9 {y}^{2} + {z}^{2} + 12xy - 6yz - 4xz$

$= > {(2x)}^{2} + {(3y)}^{2} + {(z)}^{2} + 2(2x)(3y) - 2(3y)(z) - 2(z)(2x)$

As we know that :

$(a + b - c)^2 = {a}^{2} + {b}^{2} + {c}^{2} + 2ab - 2bc - 2ca$

According to the formula we get :

$= > {(2x + 3y - z)}^{2}$

I hope it will be helpful for you ☺

Fóllòw Më❤✔