Question

factorise
4x²+y²+2²-4xy-2yz+4zx​

Answer 1

↪( 2 x )^2 + (- y ) ^2 + ( z )^2 + 2 ( 2x ) ( - y ) - 2 ( - y ) ( - z ) + 2 ( 2 x ) ( z )

↪[ 2 x + ( - y ) + z ] ^2

↪[ 2 x - y + z ] ^2

Answer 2

Answer:

$4x²+y²+2²-4xy-2yz+4zx$

$= {(2x)}^{2} + { - y}^{2} + {z}^{2} + 2(2x)( - y) + 2( - y) + (z) + 2(2x)(z)$

$= {(2x - y + z)}^{2}$

$= (2x - y + z)(2x - y + z)$

BY USING THE IDENTITY,

${(a + b + c)}^{2} = {a}^{2} + {b}^{2} + {c}^{2} + 2ab + 2bc +2 ca$