Question

factorise 4x²-y²-3xy+2x-2y​

Answer 1

Answer:

4x2−y2−3xy+2x−2y=(4x2−(4y2−3y2)−3xy+2x−2y)

=(4x2−4y2)+(3y2−3xy)+(2x−2y)=4(x2−y2)+3y(y−x)+2(x−y)

=4(x+y)(x−y)−3y(x−y)+2(x−y)=(x−y)(4(x+y)−3y+2)=(x−y)(4x+4y−3y+2)

=(x−y)(4x+y+2)