Factorise
4x²-y²+6y-9
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®4 x^2 - y^2 + 6 y - 9
=4 x^2 - ( y^2 - 6y + 9 )
=4 x^2 - ( y^2 - 2 ( y ) ( 3 ) + ( 3 )^2 )
=( 2 x )^2 - ( y - 3 )^2
use identity :
a^2 - b^2 = ( a - b ) ( a + b )
therefore ,
(2 x )^2 - ( y - 3 )^2
={ 2x - ( y - 3 ) } { 2x + ( y - 3 ) }
=( 2x - y + 3 ) ( 2x + y - 3 )
_______________________________
| : hope helps : |
_______________________________
=4 x^2 - ( y^2 - 6y + 9 )
=4 x^2 - ( y^2 - 2 ( y ) ( 3 ) + ( 3 )^2 )
=( 2 x )^2 - ( y - 3 )^2
use identity :
a^2 - b^2 = ( a - b ) ( a + b )
therefore ,
(2 x )^2 - ( y - 3 )^2
={ 2x - ( y - 3 ) } { 2x + ( y - 3 ) }
=( 2x - y + 3 ) ( 2x + y - 3 )
_______________________________
| : hope helps : |
_______________________________
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