Question

factorise:4y^2-28y+49​

Answer 1

Required answer:-

(2y - 7)²

Answer:-

Step:1

Use the sum-product pattern

=> 4y² - 28y + 49

=> 4y² - 14y - 14y + 49

Step:2

Common factor from the two pairs

=> 4y² - 14y - 14y + 49

=> 2y(2y - 7) -7(2y - 7)

Step:3

Rewrite in factored form

=> 2y(2y - 7) -7(2y - 7)

=> (2y - 7) (2y - 7)

Step:4

Combine to a square

=> (2y - 7) (2y - 7)

=> (2y - 7)²

Answer 2

Step-by-step explanation:

hope this help you

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