Question

factorise 4y^2 - 8y + 3​

Answer 1

Answer:

(2y-3)(2y-1)

Explanation:

4y²-8y+3

Splitting the middle term,we get

= 4y²-6y-2y+3

= 2y(2y-3)-1(2y-3)

= (2y-3)(2y-1)

••••

Answer 2

$\bf\huge\textbf{\underline{\underline{According\:to\:the\:Question}}}$

Factorise = 4y² - 8y + 3

Splitting the middle we get 6y - 2y

= 4y² - 6y - 2y + 3

= 2y (2y - 3) -1(2y - 3)

$\bf\huge\bf\huge{\boxed{\bigstar{{(2y \:-\:3)(2y\: - \:1)}}}}$