Math, asked by preetj641, 9 months ago

factorise 4y^3-2y^3 -4y +2​

Answers

Answered by kunalsharma949803
2

Answer:

4 {y}^{3}  - 2 {y}^{3}  - 4y + 2 \\ =  2 {y}^{3}  - 4y + 2 \\  = 2( {y}^{3}  - 2y + 1) \\  \\ the \: factors \: are \: -  \\ (2) \:and  ( {y}^{3}  - 2y + 1)

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