Question

Factorise: 4y square-4y+1

Answer 1

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Answer 2

Answer:

4y²-4y+1 = (2y-1)(2y-1)

Explanation:

Method 1:

Given quadratic expression:

4y²-4y+1

= (2y)²-2×2y×1+1²

=(2y-1)²

_______________________

By algebraic identity:

a²-2ab+b² = (a-b)²

_______________________

= (2y-1)(2y-1)

Therefore,

4y²-4y+1 = (2y-1)(2y-1)

Method 2:

4y²-4y+1

Splitting the middle term, we get

= 4y² - 2y -2y +1

= 2y(2y-1)-1(2y-1)

= (2y-1)(2y-1)

Therefore,

4y²-4y+1 = (2y-1)(2y-1)

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