Question

factorise - 4y²-4y+1​

Answer 1

Answer:

4y²-4y+1 = 0

Product = 4, Sum = -4

4y² - 2y - 2y +1 = 0

2y(2y-1) -1(2y-1) = 0

(2y - 1) (2y-1) = 0

y = 1/2 , y = 1/2

HOPE I HAVE ANSWERED YOUR QUESTION

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Answer 2

Step-by-step explanation:

$= > {2}^{2} - 4y + 1$

$= {2}^{2} {y}^{2} - 4y + {1}^{2}$

$= > 2y {)}^{2} - 4y + (1 {)}^{2}$

$= (2y {)}^{2} - 2(2y)(1) + (1 {)}^{2}$

$using \: identity \: (a + b {)}^{2} = {a}^{2} + {b}^{2} - 2ab$

$= > where \: a = 2y \\ \: \: \: \: \: \: \: \: \: b = 1$

$= > (2y - 1 {)}^{2}$

$= > (2y - 1)(2y - 1)$

HOPE THIS HEIPS U.......