factorise 4ycube -2y square - 4y+2
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Correction:
Factorize 4y³-2y²-4y+2
Solution:
Let p(y) represent the given polynomial
We have,
p(y)=4y³-2y²-4y+2
=2y²(2y-1)-2(2y-1)
=(2y²-2)(2y-1)
We know that,
•By Remainder Theorm,
Any polynomial is equal to zero
f(y)=(2y²-2)(2y-1)
→(2y²-2)(2y-1)=0
→2(y²-1)(2y-1)=0
→(y²-1)(2y-1)=0
→(y+1)(y-1)(2y-1)=0
→y=1 or -1 or -1/2
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