factorise -5-10t+20t^2
Answers
Answer:
hey mate here is ur ans
Step by step solution :
STEP
1
:
Equation at the end of step 1
(22•5t2) - (t + 12) = 0
STEP
2
:
Trying to factor by splitting the middle term
2.1 Factoring 20t2-t-12
The first term is, 20t2 its coefficient is 20 .
The middle term is, -t its coefficient is -1 .
The last term, "the constant", is -12
Step-1 : Multiply the coefficient of the first term by the constant 20 • -12 = -240
Step-2 : Find two factors of -240 whose sum equals the coefficient of the middle term, which is -1 .
-240 + 1 = -239
-120 + 2 = -118
-80 + 3 = -77
-60 + 4 = -56
-48 + 5 = -43
-40 + 6 = -34
-30 + 8 = -22
-24 + 10 = -14
-20 + 12 = -8
-16 + 15 = -1 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -16 and 15
20t2 - 16t + 15t - 12
Step-4 : Add up the first 2 terms, pulling out like factors :
4t • (5t-4)
Add up the last 2 terms, pulling out common factors :
3 • (5t-4)
Step-5 : Add up the four terms of step 4 :
(4t+3) • (5t-4)