factorise : 5-{3a^2-2a] [6-3a^2 + 2a ]
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Answered by
4
Answer:
= 5-a(14a-9a³+12a²-12)
Step-by-step explanation:
= 5-{3a^2-2a] [6-3a^2 + 2a ]
= 5- [3a²(6-3a²+2a) -2a(6-3a²+2a)]
= 5- [18a²-9a⁴+6a³-12a+6a³-4a²]
= 5- [14a²-9a⁴+12a³-12a]
= 5-a(14a-9a³+12a²-12)
Answered by
1
Answer:
= 5-{3a^2-2a] [6-3a^2 + 2a ]
= 5- [3a²(6-3a²+2a) -2a(6-3a²+2a)]
= 5- [18a²-9a⁴+6a³-12a+6a³-4a²]
= 5- [14a²-9a⁴+12a³-12a]
= 5-a(14a-9a³+12a²-12)
Step-by-step explanation:
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