Question

Factorise 5- (3a²-2a) ( 6a-3a²+2a) . Please show the steps.​

Answer 1

Answer:

heya dear here is you're answer

Answer 2

Answer:

$\bf \huge \underline {\underline{Given :- }}$

$\huge{\textsf{→}}$ 5 - 1 (3a² - 2a) (6a - 3a² + 2a)

$\bf \huge \underline {\underline{Solution :- }}$

$\huge{\textsf{→}}$ 5 - 1 (3a² - 2a) (6a - 3a² + 2a)

$\huge{\textsf{→}}$ 5 - 1 (3a² - 2a) (8a - 3a² )

$\huge{\textsf{→}}$ 5 - 1 (3a² - 2a) (-3a² + 8a)

$\huge{\textsf{→}}$ 5 - {3 (+3a² + 8a) • a² - 2a (-3a² + 8a) }

$\huge{\textsf{→}}$ 5 - {-9a⁴ + 24a³ - 2a (-3a² + 8a)}

$\huge{\textsf{→}}$ 5 - (-9a⁴ + 24a³ + 6a³ - 16a²)

$\huge{\textsf{→}}$ 5 - (-9a⁴ + 30a³ - 16a²)

$\huge{\textsf{→}}$ 5 + 9a⁴ - 30a³ + 16a²

$\huge{\textsf{→}}$ 9a⁴ - 30a³ 160² + 5

Step-by-step explanation:

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