factorise 5(3x-5y)²-20(2x-y)²
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5a^2-20b^2
5(a^2-4b^2)
put the values and solve it.
Step-by-step explanation:
first let 3x-5y=a , 2x-y=b
then the equation be 5a^2-20b^2
at last, take 5 common.
this is the answer.
mridumampi65:
can you elaborate pls
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