Question

factorise 5 - 4(a+b) - 12(a+b)² ​

Answer 1

Answer:

$5-4\left(a+b\right)-12\left(a+b\right)^2\\= -\left(12\left(a+b\right)^2+4\left(a+b\right)-5\right)\\= -\left(2\left(a+b\right)-1\right)\left(6\left(a+b\right)+5\right)\\= -\left(12a^2+24ab+12b^2+4a+4b-5\right)\\= -\left(12a^2\right)-\left(24ab\right)-\left(12b^2\right)-\left(4a\right)-\left(4b\right)-\left(-5\right)\\= -12a^2-24ab-12b^2-4a-4b+5$

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