Question

Factorise : 5√5 X^2 + 20 X + 3√5 class 9 by splitting the middle term ....pls answer my question​

Answer 1

Step-by-step explanation:

Given equation:

5√5x²+20x+3√5=0

By splitting the middle term,

5√5x²+20x+3√5=0

→5√5x²+5x+15x+3√5=0

→5x(√5x+1)+3√5(√5x+1)=0

→(√5x+1)(5x+3√5)=0

→√5x+1=0 or, 5x+3√5=0

→x= -1/√5 or, x= -3√5/5

The roots of given equation are -1/√5 and -3√5/5

Answer 2

Answer:

$5 \sqrt{5} x ^{2} + 20x + 3 \sqrt{5} \\ 5 \sqrt{5x ^{2} } + 15x + 5x + 3 \sqrt{5} \\ 5x( \sqrt{5x} + 3) + \sqrt{5} ( \sqrt{5x} + 3) \\ ( \sqrt{5x} + 3)(5x + \sqrt{5} )$