factorise 5 t square - 10 t- 390 equal to zero
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1
Answer:
it cant be solved by factorisation u can solve it by formula method or completing sq. method
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5t^2-10t-390
5(t^2-2t-78) = 0
t^2-2t-78 = 0/5
t^2-2t-78 = 0
t^2-2t = 78
one is added to both part
t^2-2t+1 = 78+1
(t-1)^2 = 79
(t-1) = √79
t = 1+√79
t = 1+8.888
t = 9.888
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