Question

factorise 5 underroot 3x^2- 32x - 7under root 3​

Answer 1

Step-by-step explanation:

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$5 \sqrt{3} {x}^{2} - 32x - 7 \sqrt{3} \\5 \sqrt{3} {x}^{2} - 35x + 3x - 7 \sqrt{3} \\ 5 {x}( \sqrt{3} x - 7) + \sqrt{3} ( \sqrt{3} x - 7) \\ (5x + \sqrt{3} )( \sqrt{3} x - 7) \\ so \: for \: zeroes \: x = \frac{ - \sqrt{3} }{5} or \: \frac{7}{ \sqrt{3} }$

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Answer 2

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Step by step solution:

$Given \ p(x)=5\sqrt{3} x^{2}- 32x - 7\sqrt{3}\\\\ we \ have \ to \ factorise \ it\\\\p(x)=5\sqrt{3} x^{2}- 32x - 7\sqrt{3}\\\\p(x)=5\sqrt{3}x^{2} -35x+3x-7\sqrt{3}\\\\p(x)=5x(\sqrt{3}x-7)+\sqrt{3}(\sqrt{3}x-7)\\\\p(x)=(5x+\sqrt{3})(\sqrt{3}-7)\\\\we \ factorised \ it$

Hope it is clear to you.