Question

Factorise 50x^2-2(x-2)^2
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Answer 1

Answer:

This is the answer

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Answer 2

Answer:

(3x-1) (2x+1)=0

Step-by-step explanation:

50x²-2(x-2)²

50x²-2(x²+4-4x)

Opening the bracket,.... we get,...

50x²-2x²-8+8x

48x²+8x-8=0

Take 8 common,....

8(6x²+x-1)=0

6x²+x-1=0/8

So finally, we get,....

6x²+x-1=0

Now, by middle term splitting:-

We require two numbers whose Product is -6 and sum or difference is 1....

So the 2 numbers are 3 and -2....

Now,

6x²+x-1=0

6x²+3x-2x-1=0

3x(2x+1) -1(2x+1)=0

(3x-1) (2x+1)=0

So (3x-1) and (2x+1) are the required factors....

HOPE IT HELPS....

THANKS....