Factorise 50x^2-2(x-2)^2
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(3x-1) (2x+1)=0
Step-by-step explanation:
50x²-2(x-2)²
50x²-2(x²+4-4x)
Opening the bracket,.... we get,...
50x²-2x²-8+8x
48x²+8x-8=0
Take 8 common,....
8(6x²+x-1)=0
6x²+x-1=0/8
So finally, we get,....
6x²+x-1=0
Now, by middle term splitting:-
We require two numbers whose Product is -6 and sum or difference is 1....
So the 2 numbers are 3 and -2....
Now,
6x²+x-1=0
6x²+3x-2x-1=0
3x(2x+1) -1(2x+1)=0
(3x-1) (2x+1)=0
So (3x-1) and (2x+1) are the required factors....
HOPE IT HELPS....
THANKS....
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