Factorise 512a^3 + 1/729b^3
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Answer:
512a³ = (8a)³
and 1/729b³ = (1/9b)³
As a³ - b³ = (a+b)(a² -ab +b²)
it is ( 8a + 1/9b)[ (8a)² - 8a.1/9b +(1/9b)²]
= (8a + 1/9b)(64a² - 8a/9b + 1/81b²)
Brainliest plz.
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