factorise 5a+20b+a³+64b³
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5a+20b+a³+64b³
= 5(a+4b) + (a)³ + (4b)³
= 5(a+4b) + (a + 4b)³ + 3 × a × 4b (a + 4b)
= 5(a+4b) + (a + 4b)³ + 12ab (a + 4b)
= (a+4b) + [5 + (a + 4b)² + 12ab]
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