Factorise 5A - 6 b whole cube minus 7c - 5 a whole cube + 6b - 7c whole cube
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3(5a-6b) (7c-5a) (6b-7c)
Step-by-step explanation:
we know that if a+b+c=0 ,than a^3 +b^3+c^3=3abc
so if we let
a=5a-6b
b=7c-5a
c=6b-7c
than,
5a-6b+7c-5a+6b-7c=0
so,
(5a-6b)^3+(7c-5a)^3 (6b-7c)^3=3abc
so we know the values of a, b, c
3(5a-6b) (7c-5a) (6b-7c) -answer
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