Factorise: 5m2 – 10 m – 240.
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Answer:
(5m ^ 2 - 10m - 240) = (5 (m² - 2m - 48))
To factor the quadratic function
m ^ 2 - 2m - 48 ,
we should solve the corresponding quadratic equation
m ^ 2 - 2m - 48 = 0
Indeed,
if m₁ and m2 are the roots of the quadratic equation
a * m ^ 2 + bm + c = 0 ,
then a * m ^ 2 + bm + c = a(m — m₁)(m – m₂) -
Solve the quadratic equation
Solve the quadratic equation m ^ 2 - 2m - 48 = 0 .
Solve the quadratic equation m ^ 2 - 2m - 48 = 0 .The roots are m_{1} = 8 , m_{2} = - 6
Therefore,
m ^ 2 - 2m - 48
= (m − 8) (m + 6)
=>
5(m ^ 2 - 2m - 48)
= 5 [(m-8) (m + 6)]
Thus,
5m^2−10m−240 = 5[(m−8)(m+6)].
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5(m(m+6)-(8m+6)
5(m-8)(m-6)
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