Question

Factorise (5p+7q)^2-(7p+5q)^2

Answer 1

$\huge\boxed{\texttt{\fcolorbox{Red}{aqua}{Hey Mate!!}}}$
$(5p + 7q) {}^{2} - (7p + 5q) {}^{2} \\ = 25p {}^{2} + 49q {}^{2} + 70pq - 49p {}^{2} - 25q {}^{2} - 70pq \\ = - 24p {}^{2} + 24q {}^{2} \\ = 24( q {}^{2} - p {}^{2} ) \\ = 24(q - p)(q + p)$
$\large{\red{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\underline{\underline{\underline{Hope\:it\:helps\: you}}}}}}}}}}}}}}}$

Answer 2

Answer:

Hope it helps u

Step-by-step explanation:

Formula applied:-:- (a+b)²=a²+2ab+b²

(25p²+70pq+49q²) - (49p²+70pq+25q²)

25p²+70pq+49q²-49q²-70pq-25q² -opening the brackets.

25p²-49p²+49q²-25q² -Rearranging the terms.(+70pq and -70pq are cancelled with each other)

-24p²+24q²

24(q²-p²)

24(q-p)(q+p)

Thank u.....