Question

Factorise 5t²+11t+6 by splitting the middle term ​

Answer 1

Answer:

3.3 Solving -5t2+11t+6 = 0 by the Quadratic Formula .

According to the Quadratic Formula, t , the solution for At2+Bt+C = 0 , where A, B and C are numbers, often called coefficients, is given by :

- B ± √ B2-4AC

t = ————————

2A

In our case, A = -5

B = 11

C = 6

Accordingly, B2 - 4AC =

121 - (-120) =

241

Applying the quadratic formula :

-11 ± √ 241

t = ——————

-10

√ 241 , rounded to 4 decimal digits, is 15.5242

So now we are looking at:

t = ( -11 ± 15.524 ) / -10

Two real solutions:

t =(-11+√241)/-10=-0.452

or:

t =(-11-√241)/-10= 2.652

thnx

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Answer 2

Answer:

(5t+6)(t+1)

Explanation:

explanation:

5t sq. + 5t + 6t + 6

5t(t+1)+6(t+1)