Question

factorise 5x^2-23x+12 by splitting the middle term ​

Answer 1

Answer: hey mate here is your answer

Step-by-step explanation:$5x^{2} -20x-3x+12$

$(5x^{2} -20x) (-3x+12)$

$5x} (x-4) -3(x-4)$

$(5x-3) ( x-4)$

therefore zeroes are x=3/5

x=4

hope this may help you

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Answer 2

Answer:We can use an AC method.

Look for a pair of factors of

A

C

=

5

⋅

12

=

60

with sum

B

=

23

.

The pair

20

,

3

works.

Use this pair to split the middle term and factor by grouping as follows:

5

x

2

−

23

x

+

12

=

5

x

2

−

20

x

−

3

x

+

12

=

(

5

x

2

−

20

x

)

−

(

3

x

−

12

)

=

5

x

(

x

−

4

)

−

3

(

x

−

4

)

=

(

5

x

−

3

)

(

x

−

4

)

Step-by-step explanation: