Question

factorise: (5x²+13-6 )by splitting the middle term​

Answer 1

Question

Factorise: (5x²+13x-6 )by splitting the middle term.

Answer

By splitting the middle term

$\bf{5x {}^{2} + 13x - 6 = 0}$

$\tt \rightarrowtail{5x {}^{2} + 13x - 6 = 0}$

$\tt \rightarrowtail{5x {}^{2} + (10 + 3)x - 6}$

$\tt \rightarrowtail{5x {}^{2} + 10x + 3x - 6 = 0}$

$\tt \rightarrowtail{5x(x + 2)+ 3(x + 2) = 0}$

$\tt \rightarrowtail{(x + 2)(5x + 3)</u><u>}$

Either,

$\tt \rightarrowtail{(x + 2) = 0} \\ \tt \rightarrowtail{x = - 2}$

Or

$\tt \rightarrowtail{ (5x + 3) = 0} \\ \tt \rightarrowtail{x = \frac{ - 3}{ \: \: 5}}$

$\tt{Hence, ~x~ is ~either~ (-2)~ or~ \frac{-3}{~5}}$