Question

factorise;5x²-20y²
please tell me the answer​

Answer 1

$\huge {5x}^{2} - 20 {y}^{2} \\ \\\huge 5( {x}^{2} - {4y}^{2} ) \\ \\ \huge5 \{ {(x)}^{2} - {(2y)}^{2} \} \\ \\ \huge5 \{(x - 2y)(x + 2y) \} \\ \\ \huge5(x + 2y)(x - 2y)$

Answer 2

Answer:

5(x + 2y)(x - 2y).

Step-by-step explanation:

Firstly, take 5 out from both terms.

5x² - 20y² = 5(x² - 4y²)

Then use the formula a² - b² = (a + b)(a - b).

We know that 4y² = (2y)².

5(x² - 4y²) = 5(x + 2y)(x - 2y)

Hence 5x² - 20y² = 5(x + 2y)(x - 2y).

Hope it helps....