factorise 5x³(2x-3)-6x³
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Answer:
Consider the given that 6x
3
−5x
2
−13x+12
Put x=1 and we get,
6(1)
3
−5(1)
2
−13(1)+12
=6−5−13+12=0
Then, x=1 and x−1=0 is a factor.
Now figure above
6x
3
−5x
2
−13x+12=(x−1)(6x
2
+x−12)=0
⇒(x−1)(6x
2
+x−12)=0
⇒(x−1)(6x
2
+(9−8)x−12)=0
⇒(x−1)(6x
2
+9x−8x−12)=0
⇒(x−1)[3x(2x+3)−4(2x+3)]=0
⇒(x−1)(3x−4)(2x+3)=0
If x−1=0 then x=1
If 3x−4=0 then x=
3
4
If 2x+3=0 then x=
2
−3
Step-by-step explanation:
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