Question

factorise 5x⁴ +x²-6​

Answer 1

Answer:

$let \: \: {x}^{2} = y \\ \\ = 5 {y}^{2} + y - 6 \\ \\ \\ \\ \\ \\ = 5 {y}^{2} - 5y + 6y - 6 \\ \\ \\ \\ \\ \\ = 5y(y - 1) + 6(y - 1) \\ \\ \\ \\ \\ \\ = (y - 1)(5y + 6) \\ \\ \\ \\ \\ replace \: y \: with \: {x}^{2} \\ \\ \\ \\ \\ \\ = ( {x}^{2} - 1)(5 {x}^{2} + 6) \\ \\ \\ \\ \\ \\ = (x - 1)(x + 1)(5 {x}^{2} + 6)$

Answer 2

Step-by-step explanation:

$(x - 1)(x + 1)(5 {x}^{2} + 6)$